CONDENSED MATTER: ELECTRONIC STRUCTURE, ELECTRICAL, MAGNETIC, AND OPTICAL PROPERTIES |
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Learning the Effective Spin Hamiltonian of a Quantum Magnet |
Sizhuo Yu1†, Yuan Gao1†, Bin-Bin Chen1, and Wei Li2,1* |
1School of Physics, Beihang University, Beijing 100191, China 2CAS Key Laboratory of Theoretical Physics, Institute of Theoretical Physics, Chinese Academy of Sciences, Beijing 100190, China
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Cite this article: |
Sizhuo Yu, Yuan Gao, Bin-Bin Chen et al 2021 Chin. Phys. Lett. 38 097502 |
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Abstract To understand the intriguing many-body states and effects in the correlated quantum materials, inference of the microscopic effective Hamiltonian from experiments constitutes an important yet very challenging inverse problem. Here we propose an unbiased and efficient approach learning the effective Hamiltonian through the many-body analysis of the measured thermal data. Our approach combines the strategies including the automatic gradient and Bayesian optimization with the thermodynamics many-body solvers including the exact diagonalization and the tensor renormalization group methods. We showcase the accuracy and powerfulness of the Hamiltonian learning by applying it firstly to the thermal data generated from a given spin model, and then to realistic experimental data measured in the spin-chain compound copper nitrate and triangular-lattice magnet TmMgGaO$_4$. The present automatic approach constitutes a unified framework of many-body thermal data analysis in the studies of quantum magnets and strongly correlated materials in general.
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Received: 10 August 2021
Express Letter
Published: 27 August 2021
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PACS: |
75.10.Dg
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(Crystal-field theory and spin Hamiltonians)
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75.10.Jm
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(Quantized spin models, including quantum spin frustration)
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75.40.Mg
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(Numerical simulation studies)
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05.70.-a
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(Thermodynamics)
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Fund: Supported by the National Natural Science Foundation of China (Grant Nos. 11974036 and 11834014). |
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[51] | In Figs. 2 and 3, we first exploit a loss function without the denominator $1/ O^{\exp}_\alpha$, i.e., $\mathcal{L}({\boldsymbol x}) = \sum_{\alpha} \sum_{T > T_{\rm cut}} \lambda_{\alpha} [O^{\exp}_\alpha(T)-O^{{\rm sim},{\boldsymbol x}}_\alpha(T)]^2$, where $\lambda_{\alpha}^{-1/2} = \max_{_{\scriptstyle T>T_{\rm cut}}} [O^{\exp}_\alpha(T), O^{{\rm sim},{\boldsymbol x}}_\alpha(T)]$. Then in Figs. 4 and 5 we follow exactly the loss definition in Eq. (1), and observe that both schemes work well. |
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